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Solution


Q.

A spring is stretched by 5 cm by a force 10 N. The time period of the oscillations when a mass of 2 kg is suspended by it is        [2021]
1 0.628 s  
2 0.0628 s  
3 6.28 s  
4 3.14 s  

Ans.

(1)

Force constant of spring, k=Fx

Here, F=10 N, x=5 cm; k=100.05=200 N/m

If the mass of 2 kg is suspended by the spring, then period of oscillation is

T=2πmk;  T=2π2200=2π×0.1

T=0.628 s