Q.

A solid sphere of mass 500 g and radius 5 cm is rotated about one of its diameter with angular speed of 10 rad s-1. If the moment of inertia of the sphere about its tangent is x×10-2 times its angular momentum about the diameter, then the value of x will be ________.          [2023]


Ans.

(35)

m=500 g=0.5 kg

R=5 cm

ω=10 rad/s

Moment of inertia about tangent=IT

IT=x×10-2L

75mR2=x×10-225mR2ω

72ω=x×10-2=72×10