A simple pendulum of length 1 m has a wooden bob of mass 1 kg. It is struck by a bullet of mass kg moving with a speed of . The bullet gets embedded into the bob. The height to which the bob rises before swinging back is

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Solution

Q.
A simple pendulum of length 1 m has a wooden bob of mass 1 kg. It is struck by a bullet of mass $10^{- 2}$ kg moving with a speed of $2 \times 10^{2}$ ${ms}^{- 1}$ . The bullet gets embedded into the bob. The height to which the bob rises before swinging back is (use $g = 10$ $m / s^{2}$ ) [2024]

1 0.30 m

2 0.20 m

3 0.35 m

4 0.40 m

Ans.
(2)

$P_{i} = P_{f} \Rightarrow m u = (M + m) V$

$m u = (M + m) V$

$10^{- 2} \times 2 \times 10^{2} ≅ 1 \times V \Rightarrow V ≅ 2 m/s$

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