A particle of mass 10 g moves in a straight line with retardation , where is the displacement in SI units. Its loss of kinetic energy for above displacement is The value of will be _________ . [2023]

Question

A particle of mass 10 g moves in a straight line with retardation $2 x$ , where $x$ is the displacement in SI units. Its loss of kinetic energy for above displacement is ${(\frac{10}{x})}^{- n} J .$ The value of $n$ will be _________ . [2023]

Smart Achievers · Accepted Answer

(2)

$Loss of K.E. = work done against retarding force$

$= \int_{0}^{x} m a d x = \int_{0}^{x} m 2 x d x = m x^{2}$

$= (10^{- 2} kg) x^{2} J = {(\frac{10}{x})}^{- 2} J$

$So n = 2$

Solution

Q.
A particle of mass 10 g moves in a straight line with retardation $2 x$ , where $x$ is the displacement in SI units. Its loss of kinetic energy for above displacement is ${(\frac{10}{x})}^{- n} J .$ The value of $n$ will be _________ . [2023]

Ans.
(2)

$Loss of K.E. = work done against retarding force$

$= \int_{0}^{x} m a d x = \int_{0}^{x} m 2 x d x = m x^{2}$

$= (10^{- 2} kg) x^{2} J = {(\frac{10}{x})}^{- 2} J$

$So n = 2$

Want Us to Email you About Special Offers & Updates?

Solution

Q. A particle of mass 10 g moves in a straight line with retardation 2x, where x is the displacement in SI units. Its loss of kinetic energy for above displacement is (10x)-nJ. The value of n will be _________ . [2023]

Ans. (2) Loss of K.E.=work done against retarding force =∫0xma dx=∫0xm2x dx=mx2 =(10-2 kg)x2J=(10x)-2J So n=2

Want Us to Email you About Special Offers & Updates?

Q.
A particle of mass 10 g moves in a straight line with retardation $2 x$ , where $x$ is the displacement in SI units. Its loss of kinetic energy for above displacement is ${(\frac{10}{x})}^{- n} J .$ The value of $n$ will be _________ . [2023]

Ans.
(2)

$Loss of K.E. = work done against retarding force$

$= \int_{0}^{x} m a d x = \int_{0}^{x} m 2 x d x = m x^{2}$

$= (10^{- 2} kg) x^{2} J = {(\frac{10}{x})}^{- 2} J$

$So n = 2$