Q.

A particle is executing SHM along a straight line. Its velocities at distances x1 and x2 from the mean position are V1 and V2, respectively. Its time period is      [2015]
 

1 2πV12+V22x12+x22  
2 2πV12-V22x12-x22  
3 2πx12+x22V12+V22  
4 2πx22-x12V12-V22  

Ans.

(4)

In SHM, velocities of a particle at distances x1 and x2 from mean position are given by

          V12=ω2(a2-x12)                        ...(i)

           V22=ω2(a2-x22)                       ...(ii)

From equations (i) and (ii), we get

         V12-V22=ω2(x22-x12)

ω=V12-V22x22-x12  T=2πx22-x12V12-V22