Q.

A parallel plate capacitor of capacitance 20 μF is being charged by a voltage source whose potential is changing at the rate of 3 V/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively        [2019]

1 zero, zero  
2 zero, 60 μA  
3 60 μA, 60 μA  
4 60 μA, zero  

Ans.

(3)

Here, C=20μF

The rate of change of potential, dVdt=3V/s

The charge on the capacitor, Q=CV

  dQdt=ID=CdVdt=20μF×3Vs=60μA

Displacement current is equal to the conduction current.