Q.

A pair of dice is thrown 5 times. For each throw, a total of 5 is considered a success. If the probability of at least 4 successes is k311, then k is equal to        [2023]

1 82  
2 164  
3 75  
4 123  

Ans.

(4)

For a total of 5 we have (1,4),(4,1),(2,3),(3,2)

So, probability of success =436=19=p

and probability of failure =89=q

Now, P(X4)=C45(19)4·(89)1+C55(19)5

k311=4095+195k=41×3=123