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Solution


Q.

A motor operating on 100 V draws a current of 1 A. If the efficiency of the motor is 91.6%, then the loss of power in units of cal/s is          [2025]
1 4  
2 8.4  
3 2  
4 6.2  

Ans.

(3)

Pinput=Vi=100 W

η=PoutPinput=0.916

Pout=ηPinput=91.6 W

Loss = 100 – 91.6 = 8.4 J/s = 2 cal/s