A metal chloride contains 55.0% of chlorine by weight. 100 mL vapours of the metal chloride at STP weigh 0.57 g. The molecular formula of the metal chloride is (Given: Atomic mass of chlorine is 35.5 u) [2023]

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Solution

Q.
A metal chloride contains 55.0% of chlorine by weight. 100 mL vapours of the metal chloride at STP weigh 0.57 g. The molecular formula of the metal chloride is (Given: Atomic mass of chlorine is 35.5 u) [2023]

1 $MCl$

2 ${MCl}_{4}$

3 ${MCl}_{2}$

4 ${MCl}_{3}$

Ans.
(3)

$Number of moles of metal chloride = \frac{100}{22400}$

$100 ml of metal chloride gives = 0.57 {g of Cl}_{2} at STP$

$So 22400 ml = 1 mole of metal chloride gives$

$= \frac{0.57}{100} \times {22400 g of Cl}_{2} at STP = 127.68 gm$

$Mass of chlorine = 55 % by mass of metal chloride$

$= \frac{55}{100} \times 127.68 = 70.224$

$Number of moles of chlorine in metal chloride$

$= \frac{70.224}{35.5} = 1.978 \approx 2$

$So, formula of metal chloride : {MCl}_{2}$

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