A long solenoid of 50 cm length having 100 turns carries a current of 2.5 A. The magnetic field at the centre of the solenoid is [2020]

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Q.
A long solenoid of 50 cm length having 100 turns carries a current of 2.5 A. The magnetic field at the centre of the solenoid is $(μ_{0} = 4 π \times 10^{- 7} T$ $m$ $A^{- 1})$ [2020]

1 $6.28 \times 10^{- 4}$ T

2 $3.14 \times 10^{- 4}$ T

3 $6.28 \times 10^{- 5}$ T

4 $3.14 \times 10^{- 5}$ T

Ans.
(1)

Here, $l = 50 cm, N = 100, i = 2.5 A$

Magnetic field inside the solenoid, $B = μ_{0} n i = \frac{μ_{0} N I}{l}$

$B = \frac{4 π \times 10^{- 7} \times 100 \times 2.5}{0.5} = 6.28 \times 10^{- 4}$ T

Solution

Q.
A long solenoid of 50 cm length having 100 turns carries a current of 2.5 A. The magnetic field at the centre of the solenoid is $(μ_{0} = 4 π \times 10^{- 7} T$ $m$ $A^{- 1})$ [2020]

1 $6.28 \times 10^{- 4}$ T

2 $3.14 \times 10^{- 4}$ T

3 $6.28 \times 10^{- 5}$ T

4 $3.14 \times 10^{- 5}$ T

Ans.
(1)

Here, $l = 50 cm, N = 100, i = 2.5 A$

Magnetic field inside the solenoid, $B = μ_{0} n i = \frac{μ_{0} N I}{l}$

$B = \frac{4 π \times 10^{- 7} \times 100 \times 2.5}{0.5} = 6.28 \times 10^{- 4}$ T

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Solution

Q. A long solenoid of 50 cm length having 100 turns carries a current of 2.5 A. The magnetic field at the centre of the solenoid is (μ0=4π×10-7T m A-1) [2020]

1 6.28×10-4T

2 3.14×10-4T

3 6.28×10-5T

4 3.14×10-5T

Ans. (1) Here, l=50cm, N=100, i=2.5A Magnetic field inside the solenoid, B=μ0ni=μ0NIl B=4π×10-7×100×2.50.5=6.28×10-4T

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Q.
A long solenoid of 50 cm length having 100 turns carries a current of 2.5 A. The magnetic field at the centre of the solenoid is $(μ_{0} = 4 π \times 10^{- 7} T$ $m$ $A^{- 1})$ [2020]

1 $6.28 \times 10^{- 4}$ T

2 $3.14 \times 10^{- 4}$ T

3 $6.28 \times 10^{- 5}$ T

4 $3.14 \times 10^{- 5}$ T

Ans.
(1)

Here, $l = 50 cm, N = 100, i = 2.5 A$

Magnetic field inside the solenoid, $B = μ_{0} n i = \frac{μ_{0} N I}{l}$

$B = \frac{4 π \times 10^{- 7} \times 100 \times 2.5}{0.5} = 6.28 \times 10^{- 4}$ T