A light ray falls on a glass surface of refractive index , at an angle 60°. The angle between the refracted and reflected rays would be [2022]

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Solution

Q.
A light ray falls on a glass surface of refractive index $\sqrt{3}$ , at an angle 60°. The angle between the refracted and reflected rays would be [2022]

1 30°

2 60°

3 90°

4 120°

Ans.
(3)

The refractive index of glass, $μ = \sqrt{3}$

Angle of incidence = $60 °$

Let $' r'$ be the angle of refraction.

Now, applying Snell's law

$1 \times \sin 60 ° = μ \times \sin r$

$\Rightarrow \frac{\sqrt{3}}{2} = \sqrt{3} \times \sin r$

$\Rightarrow \sin r = \frac{1}{2}$

$\Rightarrow r = 30 °$

Let $θ_{1} + θ_{2},$ be the angle between reflected ray and refracted ray.

Hence, from the figure we can say that

$θ_{1} + θ_{2} = 60 ° + 30 ° = 90 °$

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