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Solution


Q.

A horizontal force 10 N is applied to a block A as shown in figure. The mass of blocks A and B are 2 kg and 3 kg, respectively. The blocks slide over a frictionless surface. The force exerted by block A on block B is          [2024]


 
1 zero  
2 4 N  
3 6 N  
4 10 N  

Ans.

(3)

Common acceleration of the system,

a=10N2kg+3kg=105ms-2=2ms-2

Let R be the contact force between 2 kg and 3 kg blocks.
The free body diagram of 2 kg block is shown in the figure.

The equation of motion is,

10-R=2a or R=10-2×2=6N

So, the force exerted by block A on B = 6 N