A galvanometer having a coil of resistance 30 need 20 mA of current for full-scale deflection. If a maximum current of 3 A is to be measured using this galvanometer, the resistance of the shunt to be added to the galvanometer should be , where X is

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Solution

Q.
A galvanometer having a coil of resistance 30 $Ω$ need 20 mA of current for full-scale deflection. If a maximum current of 3 A is to be measured using this galvanometer, the resistance of the shunt to be added to the galvanometer should be $\frac{30}{X} Ω$ , where X is [2025]

1 447

2 298

3 149

4 596

Ans.
(3)

$I_{g} R_{g} = (I - I_{g}) r_{s}$

$20 \times 10^{- 3} \times 30 = (3 - 0.02) \times r_{s}$

$r_{s} = (\frac{0.6}{2.98}) = \frac{30}{x}$

$x = (\frac{2.98 \times 30}{0.6}) = 149$

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