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Solution


Q.

A force F=20+10y acts on a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from y=0 to y=1m is    [2019]
 
1 20 J  
2 30 J  
3 5 J  
4 25 J  

Ans.

(4)

Given : F=20+10y

work done, W=∫F.dy

=∫01(20+10y) dy=[20y+102y2]01=20+102=25J