A container of volume contains 0.2 mole of hydrogen gas and 0.3 mole of argon gas. The pressure of the system at temperature 200 K (R = 8.3 ) will be: [2023]

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Solution

Q.
A container of volume $200$ ${cm}^{3}$ contains 0.2 mole of hydrogen gas and 0.3 mole of argon gas. The pressure of the system at temperature 200 K (R = 8.3 ${JK}^{- 1} {mol}^{- 1}$ ) will be: [2023]

1 $6.15 \times 10^{5}$ Pa

2 $6.15 \times 10^{4}$ Pa

3 $4.15 \times 10^{5}$ Pa

4 $4.15 \times 10^{6}$ Pa

Ans.
(4)

Using ideal gas equation for mixture of two gases,

$P = \frac{(μ_{1} + μ_{2}) R T}{V}$

$= \frac{(0.2 + 0.3) \times 8.3 \times 200}{200 \times 10^{- 6}} = \frac{0.5 \times 8.3 \times 200}{200 \times 10^{- 6}}$

$P = 4.15 \times 10^{6}$ $Pa$

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