A compound X contains 32% of A, 20% of B and remaining percentage of C. Then, the empirical formula of X is (Given atomic masses of A = 64, B = 40, C = 32 u) [2024]

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Solution

Q.
A compound X contains 32% of A, 20% of B and remaining percentage of C. Then, the empirical formula of X is

(Given atomic masses of A = 64, B = 40, C = 32 u) [2024]

1 $A_{2} B C_{2}$

2 $A B C_{3}$

3 $A B_{2} C_{2}$

4 $A B C_{4}$

Ans.
(2)

Element % At. Mass Molar Ratio Simplest Ratio

A 32 64 $\frac{32}{64} = \frac{1}{2}$ 1

B 20 40 $\frac{20}{40} = \frac{1}{2}$ 1

C 48 32 $\frac{48}{32} = \frac{3}{2}$ 3

Thus, empirical formula of compound is ${ABC}_{3} .$

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