A coil having 100 turns, area of , carrying current of 1 mA is placed in a uniform magnetic field of 0.20 T in such a way that plane of coil is perpendicular to the magnetic field. The work done in turning the coil through 90° is ____ ?J

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Solution

Q.
A coil having 100 turns, area of $5 \times 10^{- 3}$ $m^{2}$ , carrying current of 1 mA is placed in a uniform magnetic field of 0.20 T in such a way that plane of coil is perpendicular to the magnetic field. The work done in turning the coil through 90° is ____ μJ. [2024]

Ans.
(100) $W = Δ U = U_{f} - U_{i}$

$W = | M B \cos 90 ° - M B \cos 0 ° | = M B$

$W = (NIA) B = (100 \times 5 \times 10^{- 3} \times 1 \times 10^{- 3}) \times 0.2 J$

$= 1 \times 10^{- 4} J = 100 μ J$

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