Q.

A coil has an inductance of 2 H and resistance of 4Ω. A 10 V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be _________ ×10-2 J.                          [2023]


Ans.

(625)

I=VR=52 A

E=12LI2=12×2×(52)2

E=625×10-2 J