Q.

A circular disk of radius R meter and mass M kg is rotating around the axis perpendicular to the disk. An external torque is applied to the disk such that θ(t)=5t28t, where θ(t) is the angular position of the rotating disc as a function of time t. How much power is delivered by the applied torque, when t = 2 s          [2025]

1 60MR2  
2 72MR2  
3 108MR2  
4 8MR2  

Ans.

(1)

Given: θ=5t28t

ω=dθdt=10t8

α=dωdt=10 rads2

Power, P=τω=(Iα)ω

 P=(MR22)αω=(MR22)(10)(10t8)

Put t = 2 s, P=60MR2