A charge of 4.0 ?C is moving with a velocity of 4.0 × 10? ms?¹ along the positive y-axis under a magnetic field of strength (2k?) T. The force acting on the charge is N. The value of is

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Solution

Q.
A charge of 4.0 μC is moving with a velocity of $4.0 \times 10^{6} m s^{- 1}$ along the positive y-axis under a magnetic field $\vec{B}$ of strength ( $2 \hat{k}$ ) T. The force acting on the charge is $x \hat{i}$ N. The value of $x$ is ____. [2024]

Ans.
(32) $q = 4 μ C, \vec{v} = 4 \times 10^{6} \hat{j} m / s,$ $\vec{B} = 2 \hat{k} T$

$\vec{F} = q (\vec{v} \times \vec{B}) = 4 \times 10^{- 6} (4 \times 10^{6} \hat{j} \times 2 \hat{k})$

$\vec{F} = 4 \times 10^{- 6} \times 8 \times 10^{6} \hat{i} = 32 \hat{i} N$

$x = 32$

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