Q.

A certain elastic conducting material is stretched into a circular loop. It is placed with its plane perpendicular to a uniform magnetic field B = 0.8 T. When released, the radius of the loop starts shrinking at a constant rate of 2 cm s-1. The induced emf in the loop at an instant when the radius of the loop is 10 cm will be ________ mV.        [2023]


Ans.

(10)

EMF=ddt(Bπr2)

          =2Bπrdrdt=2×π×0.1×0.8×2×10-2

          =2π×1.6=10.06  [round off 10.06=10]