A bullet is fired from a gun at the speed of in the direction above the horizontal. The maximum height attained by the bullet is [2023]

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Solution

Q.
A bullet is fired from a gun at the speed of $280 {ms}^{- 1}$ in the direction $30 °$ above the horizontal. The maximum height attained by the bullet is $(g = 9.8 {ms}^{- 2}, \sin 30 ° = 0.5)$ [2023]

1 1000 m

2 3000 m

3 2800 m

4 2000 m

Ans.
(1)

Maximum height attained by projectile, is $H = \frac{u^{2} \sin^{2} θ}{2 g}$

Given that, $u = 280 {ms}^{- 1}$ and $θ = 30 °$

$∴ H = \frac{{(280)}^{2} \times \sin^{2} 30 °}{2 \times 9.8} = \frac{{(280)}^{2} \times (0.25)}{2 \times 9.8} = 1000 m$

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