Q.

A body of mass (5 ± 0.5) kg is moving with a velocity of (20 ± 0.4) m/s. Its kinetic energy will be          [2023]

1 (1000 ± 140) J  
2 (1000 ± 0.14) J  
3 (500 ± 0.14) J  
4 (500 ± 140) J  

Ans.

(1)

k=12mv2

k=12×5×400=5×200=1000 J

kk=mm+2vv=0.55+2×0.420

k=1000(110+4100)=1000(10+4100)=140 J