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Solution


Q.

A ball is projected with a velocity, 10ms-1 at an angle of 60° with the vertical direction. Its speed at the highest point of its trajectory will be:        [2022]
1 zero  
2 53ms-1  
3 5ms-1  
4 10ms-1  

Ans.

(2)

Ball is projected with a velocity, u=10m/s

Angle of projection, θ=90°-60°=30°

The velocity of a projectile at the highest point will be v=ucosθ=10×cos30°

=10×32=53m/s