A 400 g solid cube having an edge of length 10 cm floats in water. How much volume of the cube is outside the water? (Given: density of water = 1000 kg ) [2025]

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Solution

Q.
A 400 g solid cube having an edge of length 10 cm floats in water. How much volume of the cube is outside the water (Given: density of water = 1000 kg $m^{- 3}$ ) [2025]

1 1400 ${cm}^{3}$

2 4000 ${cm}^{3}$

3 400 ${cm}^{3}$

4 600 ${cm}^{3}$

Ans.
(4)

Volume of cube inside water

$V_{cube, in} = (\frac{Density of cube}{Density of water}) \times Volume of cube$

$= \frac{Mass of cube}{Density of water} = \frac{400 gm}{1 gm / {cm}^{3}} = 400 {cm}^{3}$

Volume of cube outside water

$V_{cube, out}$ = Volume of cube – Volume of cube inside water

= 1000 ${cm}^{3}$ – 400 ${cm}^{3}$ = 600 ${cm}^{3}$

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