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Solution


Q.

A 40 μF capacitor is connected to a 200 V, 50 Hz AC supply. The r.m.s. value of the current in the circuit is, nearly              [2020]
 
1 1.7 A  
2 2.05 A  
3 2.5 A  
4 25.1 A  

Ans.

(3)

Here, C=40 μF=40×10-6F

Vrms=200V;  υ=50Hz

The value of the current, Irms=εrms1ωC=εrmsωC

or   Irms=200×(2π×50)×(40×10-6)=2.51 A  (∵ω=2πυ)