Q.

A 12 pF capacitor is connected to a 50 V battery, the electrostatic energy stored in the capacitor in nJ is         [2024]

1 15  
2 7.5  
3 0.3  
4 150  

Ans.

(1)

Capacitance, (C) =12 pF=12×10-12 F

Voltage of Battery, (V) =50 V

Energy stored in capacitor, (U) =12CV2

U=12×(12×10-12)(50)2=150×10-10 J=15×10-9J=15 nJ