80 mole percent of MgCl2 is dissociated in aqueous solution. The vapour pressure of 1.0 molal aqueous solution of MgCl2 at 38°C is ______ mm Hg. (Nearest integer)
Given: Vapour pressure of water at 38°C is 50 mm Hg. [2023]
(48)
MgCl2→Mg2++2Cl-1-αα2αi=1+2α(∵α=0.8)i=2.6
ΔPP0=i×n2n1=2.6×155.5=0.0468
50-PsPs=0.0468
1.0468 Ps=50
Ps=47.76≈48 mm Hg