Q.

 60π|(sin3x+sin2x+sinx)|dx is equal to_____.    [2026]


Ans.

(17)

60π|2sin2xcosx+sin2x|dx

=60π|4sinxcos2x+2sinxcosx|dx

I=120π|sinx(2cos2x+cosx)|dx

Put cosx=t,  -sinxdx=dt

I=-121-1|2t2+t|dt

I=12(-1-12(2t2+t)dt+-120-(2t2+t)dt+01(2t2+t)dt)

I=17