20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is ______ M. (Nearest integer) [2025]

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Solution

Q.
20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is ______ $\times 10^{- 2}$ M. (Nearest integer) [2025]

Ans.
(57)

$Final concentration = \frac{M_{1} V_{1} + M_{2} V_{2}}{V_{1} + V_{2}}$

$= \frac{2 \times 20 + 0.5 \times 400}{20 + 400} M$

$= \frac{240}{420} M = 0.571 M = 57.1 \times 10^{- 2} M$

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