2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is: (Given: Ebulioscopic constant of water = 0.52 K kg ) [2025]

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Solution

Q.
2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is:

(Given: Ebulioscopic constant of water = 0.52 K kg ${mol}^{- 1}$ ) [2025]

1 379.2 K

2 377.3 K

3 375.3 K

4 277.3 K

Ans.
(2)

Total moles of solute $= 2 mol glycol+ 2 mol glucose = 4 mol$

Molality of solution $(m)$

$= \frac{Total moles of electrolyte}{Mass of solvent in gm} \times 1000$

$= \frac{4}{500} \times 1000 = 8 m$

Elevation in boiling point, $Δ T_{b} = m K_{b} = 8 \times 0.52 K = 4.16 K$

Boiling point of solution $(T_{b} (solution))$

$= T_{b} (water) + Δ T_{b} = (373.15 + 4.16) K = 377.31 K$

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