17 mg of a hydrocarbon (M.F. ) takes up 8.40 mL of the gas measured at 0°C and 760 mm of Hg. Ozonolysis of the same hydrocarbon yields, The number of double bond/s present in the hydrocarbon is ________. [2023]

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Solution

Q.
17 mg of a hydrocarbon (M.F. $C_{10} H_{16}$ ) takes up 8.40 mL of the $H_{2}$ gas measured at 0°C and 760 mm of Hg. Ozonolysis of the same hydrocarbon yields

The number of double bond/s present in the hydrocarbon is ________. [2023]

Ans.
(3)

$C_{10} H_{16}$ has DU = 3

Now millimoles of hydrocarbon and $H_{2}$ gas are as follows respectively:

millimoles of hydrocarbon $= \frac{17}{136} = 0.125$

$\frac{8.40}{22400} \times 10^{3} = 0.375 millimoles of H_{2} gas$

Hence, they are in ratio 1 : 3 to confirm $3 π$ bonds in molecules.

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