10 mL of 2 M NaOH solution is added to 20 mL of 1 M HCl solution kept in a beaker. Now, 10 mL of this mixture is poured into a volumetric flask of 100 mL containing 2 moles of HCl and made the volume upto the mark with distilled water. The solution in thi

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Solution

Q.
10 mL of 2 M NaOH solution is added to 20 mL of 1 M HCl solution kept in a beaker. Now, 10 mL of this mixture is poured into a volumetric flask of 100 mL containing 2 moles of HCl and made the volume upto the mark with distilled water. The solution in this flask is : [2025]

1 0.2 M NaCl solution

2 20 M HCl solution

3 10 M HCl solution

4 Neutral solution

Ans.
(2)

Final solution contains 2 mol HCl in 100 mL of solution (0.1 L solution). So concentration of final solution is $\frac{n_{HCl}}{V_{solution} (in L)} = \frac{2}{0.1} M = 20 M$

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