1 L, 0.02 M solution of is mixed with 1 L, 0.02 M solution of . The resulting solution is divided into two equal parts (X) and treated with excess of solutions and solution respectively as shown below: 1 L Solutions (X) + solution (excess)

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Solution

Q.
1 L, 0.02 M solution of $[Co {({NH}_{3})}_{5} {SO}_{4}] Br$ is mixed with 1 L, 0.02 M solution of $[Co {({NH}_{3})}_{5} Br] {SO}_{4}$ . The resulting solution is divided into two equal parts (X) and treated with excess of ${AgNO}_{3}$ solutions and ${BaCl}_{2}$ solution respectively as shown below:

1 L Solutions (X) + ${AgNO}_{3}$ solution (excess) $\to$ Y

1 L Solutions (X) + ${BaCl}_{2}$ solution (excess) $\to$ Z

The number of moles of Y and Z respectively are [2023]

1 0.02, 0.02

2 0.02, 0.01

3 0.01, 0.01

4 0.01, 0.02

Ans.
(3)

On mixing equal volume, concentration is half.

$[Co {({NH}_{3})}_{5} {SO}_{4}] Br,$ $[Co {({NH}_{3})}_{5} Br] {SO}_{4}$

0.01 M 0.01 M

$(i)$ $X [Co {({NH}_{3})}_{5} {SO}_{4}] Br + {AgNO}_{3} ⟶ AgBr ↓$

$(\frac{0.02}{2}) mole$ $\underset{' Y'}{0.01 mole}$

$(ii)$ $X [Co {({NH}_{3})}_{5} Br] {SO}_{4} + {BaCl}_{2} ⟶ {BaSO}_{4} ↓$

$(\frac{0.02}{2}) mole$ $\underset{' Y'}{0.01 mole}$

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