Q.

1 g of a liquid is converted to vapour at 3×105 Pa pressure. If 10% of the heat supplied is used for increasing the volume by 1600 cm3 during this phase change, then the increase in internal energy in the process will be:          [2023]

1 4800 J  
2 4320 J  
3 4.32×108 J  
4 432000 J  

Ans.

(2)

Work done=PΔV

                     =3×105×1600×10-6=480 J

Only 10% of heat is used in work done.

Hence ΔQ=4800 J

The rest goes into internal energy, which is 90% of heat.

Change in internal energy=0.9×4800=4320 J