0.5 g of an organic compound on combustion gave 1.46 g of and 0.9 g of . The percentage of carbon in the compound is _____. (Nearest integer) [Given: Molar mass (in g ) C : 12, H : 1, O : 16] [2025]

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Solution

Q.
0.5 g of an organic compound on combustion gave 1.46 g of ${CO}_{2}$ and 0.9 g of $H_{2} O$ . The percentage of carbon in the compound is _____. (Nearest integer)

[Given: Molar mass (in g ${mol}^{- 1}$ ) C : 12, H : 1, O : 16] [2025]

Ans.
(80)

Moles of carbon in organic compound ( $n_{C}$ ) = moles of carbon in ${CO}_{2}$

$=Moles of C O_{2} = \frac{Mass of C O_{2}}{Molar mass of C O_{2}} = \frac{1.46}{44} mol$

Mass of carbon in organic compound ( $W_{C}$ ) $= n_{C} \times Molar mass of C = \frac{1.46}{44} \times 12 g$

Percentage of carbon in organic compound

$= \frac{Mass of carbon in organic compound}{Mass of organic compound} \times 100$

$= \frac{1.46 \times 12}{44 \times 0.5} \times 100 = 79.63 % \approx 80 %$

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