0.400 g of an organic compound (X) gave 0.376 g of AgBr in Carius method for estimation of bromine. % of bromine in the compound (X) is __________. (Given: Molar mass AgBr = 188 g , Br = 80 g ) [2023]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
0.400 g of an organic compound (X) gave 0.376 g of AgBr in Carius method for estimation of bromine. % of bromine in the compound (X) is __________.

(Given: Molar mass AgBr = 188 g ${mol}^{- 1}$ ,

Br = 80 g ${mol}^{- 1}$ ) [2023]

Ans.
(40)

$Organic compound (X) \overset{{Ag}^{+}}{\to} AgBr$

0.40 gram 0.376 gram

$Mole of AgBr = \frac{0.376}{188} = 0.002$

$Mole of Br = 0.002$

$Mass of Br = 0.002 \times 80 = 0.16 g$

$% of Br = \frac{0.16}{0.4} \times 100 = 40 %$

Want Us to Email you About Special Offers & Updates?