0.004 M K 2 SO 4 solution is isotonic with 0.01 M glucose solution. Percentage dissociation of K 2 SO 4 is _______% (Nearest integer) [2023]

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Solution

Q.
0.004 M $K_{2} {SO}_{4}$ solution is isotonic with 0.01 M glucose solution. Percentage dissociation of $K_{2} {SO}_{4}$ is _______% (Nearest integer) [2023]

Ans.
(75)

$Isotonic solution,$

$π_{K_{2} S O_{4}} = π_{Glucose}$

$i \times 0.004 \times R T = 0.01 \times R T$

$i = 2.5$

For $K_{2} S O_{4}$ {for dissociation $i = 1 + (n - 1) α$ }

$DOD (α) = \frac{i - 1}{n - 1} = \frac{2.5 - 1}{3 - 1} = 0.75$

$% dissociation = 75$

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