Q 1 :    

In an experiment to measure focal length (f) of convex lens, the least count of the measuring scales for the position of object (u) and for the position of image (v) are u and v, respectively. The error in the measurement of the focal length of the convex lens will be                            [2024]

  • 2f[uu+vv]

     

  • f[uu+vv]

     

  • uu+vv

     

  • f2[uu2+vv2]

     

(D) 1v-1u=1f

       -1v2dv+1u2du=-1f2df dff2=dvv2+duu2

       df=f2[dvv2+duu2]f=f2(vv2+uu2)

 



Q 2 :    

To find the spring constant (k) of a spring experimentally, a student commits 2% positive error in the measurement of time and 1% negative error in measurement of mass. The percentage error in determining value of k is:                                    [2024]

  • 3%

     

  • 4%

     

  • 5%

     

  • 1%

     

(A)  T=2πmkk=4π2·mT2

        kk=mm+2·TTkk%=mm%+2TT%

        (We always take maximum error)

        kk%=(-1)%+2(2)%=|-3%|=3%



Q 3 :    

Young's modulus is determined by the equation given by Y=49000mLdynecm2 where M is the mass and L is the extension of wire used in the experiment. Now error in Young's modules (Y) is estimated by taking data from M-L plot in graph paper. The smallest scale divisions are 5g and 0.02 cm along load axis and extension axis respectively. If the value of M and are 500 g and 2 cm respectively then percentage error of Y is                      [2024]

  • 0.2%

     

  • 0.02%

     

  • 2%

     

  • 0.5%

     

(C)  YY=mm+ll

        =5500+0.022=0.01+0.01YY

        %YY=2%



Q 4 :    

The resistance R=V/I where V=(200±5)V and I=(20±0.2)A. The percentage error in the measurement of R is:              [2024]

  • 3.5%

     

  • 7%

     

  • 3%

     

  • 5.5%

     

(A)  We have, R=V/I

       According to error analysis, maximum fractional error.

       dRR=dVV+dII

       dRR=5200+0.220=7200

        Hence, % error dRR×100=7200×100=3.5%



Q 5 :    

A physical quantity Q is found to depend on quantities a,b,c by the relation Q=a4b3c2. The percentage error in a,b and c are 3%, 4% and 5% respectively. Then, the percentage error in Q is                                       [2024]

  • 66%

     

  • 14%

     

  • 34%

     

  • 43%

     

(C)  QQ=4aa+3bb+2cc

      Q=4×3%+3×4%+2×5%

       =12%+12%+10%=34%

        

 



Q 6 :    

If the percentage errors in measuring the length and the diameter of a wire are 0.1% each. The percentage error in measuring its resistance will be          [2024]

  • 0.2%

     

  • 0.144%

     

  • 0.3%

     

  • 0.1%

     

(C)  R=ρLπd24

        RR=LL+2dd

        LL=0.1% and dd=0.1%

         RR=0.3%



Q 7 :    

The measured value of the length of a simple pendulum is 20 cm with 2 mm accuracy. The time for 50 oscillations was measured to be 40 seconds with 1 second resolution. From these measurements, the accuracy in the measurement of acceleration due to gravity is N%. The value of N is:                    [2024]

  • 4

     

  • 8

     

  • 6

     

  • 5

     

(C)  T=2πlg

        g=4π2lT2

        gg=ll+2TT=0.220+2(140)=1.220

        Percentage change = 1.220×100=6%



Q 8 :    

The radius (r), length (l) and resistance (R) of a metal wire was measured in the laboratory as                              [2024]

 

r=(0.35±0.05)cm

 

R=(100±10)ohm

 

l=(15±0.2)cm

 

The percentage error in resistivity of the material of the wire is

  • 25.6%

     

  • 39.9%

     

  • 37.3%

     

  • 35.6%

     

(B)  ρρ=RR+2rr+ll

        =10100+2×0.050.35+0.215

         =110+27+175

          ρρ=39.9%