Q 1 :    

If the molar conductivity (Λm) of a 0.050 mol L-1 solution of a monobasic weak acid is 90 S cm2 mol-1, its extent (degree) of dissociation will be

[Assume Λ+=349.6 S cm2 mol-1 and Λ-=50.4 S cm2 mol-1]                   [2025]

  • 0.225

     

  • 0.215

     

  • 0.115

     

  • 0.125

     

(1)

Given: Concentration of solution = 0.050 mol L-1

Λm=90 S cm2 mol-1

Λmo=Λ+o+Λ-o

=349.6+50.4=400 S cm2 mol-1

α=ΛmΛmo=90400=0.225

 



Q 2 :    

Molar conductance of an electrolyte increases with dilution according to the equation:

Λm=Λm-Ac

Which of the following statements are true? 

(A) This equation applies to both strong and weak electrolytes.  
(B) Value of the constant A depends upon the nature of the solvent.  
(C) Value of constant A is same for both BaCl2 and MgSO4.  
(D) Value of constant A is same for both BaCl2 and Mg(OH)2.  

Choose the most appropriate answer from the options given below:            [2023]

  • (A) and (B) only

     

  • (A), (B) and (C) only

     

  • (B) and (C) only

     

  • (B) and (D) only

     

(4)

The given equation is applicable only to strong electrolytes. For strong electrolytes, Λm increases slowly with dilution and thus is represented by the given equation. The value of the constant 'A' for a given solvent and temperature depends on the type of electrolyte, i.e., the charge on the cation and anion produced on the dissociation of the electrolyte in the solution. Value of constant 'A' is same for both BaCl2 and Mg(OH)2.

 



Q 3 :    

The conductivity of centimolar solution of KCl at 25 C is 0.0210 ohm-1 cm-1 and the resistance of the cell containing the solution at 25C is 60 ohm. The value of cell constant is                 [2023]

  • 1.26 cm-1

     

  • 3.34 cm-1

     

  • 1.34 cm-1

     

  • 3.28 cm-1

     

(1)

Given, κ=0.0210 ohm-1 cm-1, R=60 ohm

κ=1R×la  (where la=cell constant)

or       0.0210=160×la

or       la=60×0.0210=1.26 cm-1



Q 4 :    

The molar conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 426.16 and 91.0 S cm2 mol-1 respectively. The molar conductance of CH3COOH at infinite dilution is.  Choose the right option for your answer.            [2021]

  • 540.48 S cm2 mol-1

     

  • 201.28 S cm2 mol-1

     

  • 390.71 S cm2 mol-1

     

  • 698.28 S cm2 mol-1

     

(3)

ΛCH3COOH∞ =ΛCH3COONa∘+ΛHCl∘-ΛNaCl∘

                      =91.0+426.16-126.45

                      =390.71 S cm2 mol-1



Q 5 :    

The molar conductivity of 0.007 M acetic acid is 20 S cm2 mol-1. What is the dissociation constant of acetic acid?  Choose the correct option.

[ΛH+=350 S cm2 mol-1ΛCH3COO-=50 S cm2 mol-1]                                 [2021]

  • 2.50×10-5 mol L-1

     

  • 1.75×10-4 mol L-1

     

  • 2.50×10-4 mol L-1

     

  • 1.75×10-5 mol L-1

     

(4)

Λm(CH3COOH)∘ =λH+∘+λCH3COO-∘

                          =350+50=400 S cm2 mol-1

Degree of dissociation, α=ΛmcΛmo=20400=0.05

So, dissociation constant, Ka=cα2  (for weak electrolytes)

                                               =0.007(0.05)2=1.75×10-5 mol L-1



Q 6 :    

Following limiting molar conductivities are given as:  

λm(H2SO4)=x S cm2 mol-1

λm(K2SO4)=y S cm2 mol-1

λm(CH3COOK)=z S cm2 mol-1

λm (in S cm2 mol-1) for CH3COOH will be                   [2019]

  • x-y+2z

     

  • x+y-z

     

  • x-y+z

     

  • (x-y)2+z

     

(4)

According to Kohlrausch's law,  

Λmo for CH3COOH =λCH3COO-∘+λH+∘

Λ° for H2SO4 =2λH+∘+λSO42-∘=x S cm2 mol-1             ...(i)

Λ° for K2SO4 =2λK+∘+λSO42-∘=y S cm2 mol-1             ...(ii)

Λ° for CH3COOK =λCH3COO-∘+λK+∘=z S cm2 mol-1        ...(iii)

On adding equation (i) and 2×(iii) and subtracting (ii), we get  

2λH+∘+λSO42-∘ +2λCH3COO-∘ +2λK+∘ -2λK+∘ -λSO42-∘ =x+2z-y

2λH+∘+2λCH3COO-∘=x+2z-y

λH+∘+λCH3COO-∘ =(x-y)2+z



Q 7 :    

The molar conductivity of a 0.5 mol/dm3 solution of AgNO3, with electrolytic conductivity of 5.76 ×10-3 S cm-1 at 298 K is          [2016]

  • 2.88 S cm2/mol

     

  • 11.52 S cm2/mol

     

  • 0.086 S cm2/mol

     

  • 28.8 S cm2/mol

     

(2)

Λm=κ×1000Molarity(M)

       =5.76×10-3 S cm-1×10000.5 mol cm-3=11.52 S cm2 mol-1