Q 1 :    

The electric current through a wire varies with time as I=I0+βt where I0=20A and β=3A/s. The amount of electric charge crossed through a section of the wire in 20 sec is                           [2024]

  • 80 C

     

  • 1000 C

     

  • 800 C

     

  • 1600 C

     

(B)       Given that, current I=I0+βt

            Also, I0=20A and β=3A/s

            Hence, dq/dt=20+3tdq=(20+3t)dt

            0qdq=020(20+3t)dt

            q=[20t+3t22]020=1000C

 



Q 2 :    

The current in a conductor is expressed as I=3t2+4t3, where I is in Ampere and t is in second. The amount of electric charge that flows through a section of the conductor during t=1s to t=2s is _________ C.               [2024]



(22)       I=3t2+4t3

              dQ=Idt

              Q=12(3t2+4t3)dt

                   =[t3+t4]12

                    =(8+16)-(2)=22C