Q 1 :    

The electric current through a wire varies with time as I=I0+βt where I0=20A and β=3A/s. The amount of electric charge crossed through a section of the wire in 20 sec is                           [2024]

  • 80 C

     

  • 1000 C

     

  • 800 C

     

  • 1600 C

     

(2)       

           Given that, current I=I0+βt

            Also, I0=20A and β=3A/s

            Hence, dq/dt=20+3tdq=(20+3t)dt

            0qdq=020(20+3t)dt

            q=[20t+3t22]020=1000C

 



Q 2 :    

The current in a conductor is expressed as I=3t2+4t3, where I is in Ampere and t is in second. The amount of electric charge that flows through a section of the conductor during t=1s to t=2s is _________ C.               [2024]



(22)       I=3t2+4t3

              dQ=Idt

              Q=12(3t2+4t3)dt

                   =[t3+t4]12

                    =(8+16)-(2)=22C

 



Q 3 :    

Which of the following resistivity (ρ) v/s temperature (T) curve is most suitable to be used in wire bound standard resistors?          [2025]

  •  

  •  

  •  

  •  

(1)

For bound standard resistors the resistivity is independent of temperature and remain nearly constant.



Q 4 :    

The difference of temperature in a material can convert heat energy into electrical energy. To harvest the heat energy, the material should have          [2025]

  • low thermal conductivity and low electrical conductivity

     

  • high thermal conductivity and high electrical conductivity

     

  • low thermal conductivity and high electrical conductivity

     

  • high thermal conductivity and low electrical conductivity

     

(3)

Material should have low thermal conductivity and high electrical conductivity.



Q 5 :    

Current passing through a wire as function of time is given as I(t) = 0.02 t + 0.01 A. The charge that will flow through the wire from t = 1s to t = 2s is:          [2025]

  • 0.06 C

     

  • 0.02 C

     

  • 0.07 C

     

  • 0.04 C

     

(4)

q=idt=12(0.02t+0.01)dt

q=[0.02t22+0.01t]12

     =0.022×(2212)+0.01×1=0.04 C