jee main chemistry important questions | Chemical Bonding And Molecular Structure

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Topic Question Set

Q 1 :
Number of molecules/species from the following having one unpaired electron is __________.

$O_{2}, O_{2}^{- 1}, NO, {CN}^{- 1}, O_{2}^{2 -}$ [2024]

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Molecules	Number of electrons	Electronic configuration	Number of unpaired electrons
$O_{2}$	16	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < π^{} 2 p_{x}^{1} = π^{} 2 p_{y}^{1}$	2
$O_{2}^{-}$	17	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < π^{} 2 p_{x}^{2} = π^{} 2 p_{y}^{1}$	1
$NO$	15	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < π^{} 2 p_{x}^{1} = π^{} 2 p_{y}^{0}$	1
${CN}^{-}$	14	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < σ 2 p_{z}^{2}$	0
$O_{2}^{2 -}$	18	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < π^{} 2 p_{x}^{2} = π^{} 2 p_{y}^{2}$	0

Q 2 :
Number of molecules having bond order 2 from the following molecule is _________ .

$C_{2}, O_{2}, B e_{2}, L i_{2}, N e_{2}, N_{2}, H e_{2}$ [2024]

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Molecule	Electronic configuration	Bond order $= \frac{1}{2} [N_{b} - N_{a}]$
$C_{2}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2}$	$\frac{1}{2} [8 - 4] = 2$
$O_{2}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < π^{} 2 p_{x}^{1} = π^{} 2 p_{y}^{1}$	$\frac{1}{2} [10 - 6] = 2$
${Be}_{2}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2}$	$\frac{1}{2} [4 - 4] = 0$
${Li}_{2}$	$σ 1 s^{2} < σ^{*} 1 s^{2} < σ 2 s^{2}$	$\frac{1}{2} [4 - 2] = 1$
${Ne}_{2}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < π^{} 2 p_{x}^{2} = π^{} 2 p_{y}^{2} < σ^{*} 2 p_{z}^{2}$	$\frac{1}{2} [10 - 10] = 0$
$N_{2}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < σ 2 p_{z}^{2}$	$\frac{1}{2} [10 - 4] = 3$
${He}_{2}$	$σ 1 s^{2} < σ^{*} 1 s^{2}$	$\frac{1}{2} [2 - 2] = 0$

Q 3 :
The total number of species from the following in which one unpaired electron is present, in ____________ .

$N_{2}, O_{2}, C_{2}^{-}, O_{2}^{-}, O_{2}^{2 -}, H_{2}^{+}, {CN}^{-}, {He}_{2}^{+}$ [2024]

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Molecule	Electronic configuration	Number of unpaired electrons
$N_{2}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < σ 2 p_{z}^{2}$	0
$O_{2}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < π^{} 2 p_{x}^{1} = π^{} 2 p_{y}^{1}$	2
$C_{2}^{-}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < σ 2 p_{z}^{1}$	1
$O_{2}^{-}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < π^{} 2 p_{x}^{2} = π^{} 2 p_{y}^{1}$	1
$O_{2}^{2 -}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < π^{} 2 p_{x}^{2} = π^{} 2 p_{y}^{2}$	0
$H_{2}^{+}$	$σ 1 s^{1}$	1
${CN}^{-}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < σ 2 p_{z}^{2}$	0
${He}_{2}^{+}$	$σ 1 s^{2} < σ^{*} 1 s^{1}$	1

Q 4 :
Total number of electrons present in $(π^{*})$ molecular orbitals of $O_{2}, O_{2}^{+}$ and $O_{2}^{-}$ is _________ . [2024]

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Molecule	Electronic configuration	*Electrons present in $π^{}$**
$O_{2}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < π^{} 2 p_{x}^{1} = π^{} 2 p_{y}^{1}$	2
$O_{2}^{+}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < π^{} 2 p_{x}^{1} = π^{} 2 p_{y}^{0}$	1
$O_{2}^{-}$	$σ 1 s^{2} < σ^{} 1 s^{2} < σ 2 s^{2} < σ^{} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < π^{} 2 p_{x}^{2} = π^{} 2 p_{y}^{1}$	3

Sum = 2 + 1 + 3 = 6

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