Choose the polar molecule from the following. [2024]
(4)
In , and , individual bond moments cancel out to give a net zero dipole moment. In , because it is not a symmetrical molecule, vector sum of bond moments is not zero i.e. it is a polar molecule.
Given below are two statements:
Statement - I: Since Fluorine is more electronegative than nitrogen, the net dipole moment of is greater than .
Statement - II: In , the orbital dipole due to lone pair and the dipole moment of NH bonds are in opposite direction, but in the orbital dipole due to lone pair and dipole moments of N-F bonds are in same direction.
In the light of the above statements, choose the most appropriate from the options given below: [2024]
Statement I is true but Statement II is false.
Both Statement I and Statement II are false.
Both Statement I and Statement II are true.
Statement I is false but Statement II is true.
(2)
In , lone pair moment and bond pair moments are in opposite direction but in , lone pair moment and bond pair moments are in same direction. Hence resultant dipole moment in is more.
Number of molecules/ions from the following in which the central atom is involved in hybridization is ________.
[2024]
3
2
1
4
(2)
The number of species from the following that have pyramidal geometry around the central atom is ________.
[2024]
1
2
3
4
(1)
Match List-I with List-II.
| List-I | List-II | ||
| A. | I. | T-shape | |
| B. | II. | Square pyramidal | |
| C. | III. | Pentagonal bipyramidal | |
| D. | IV. | Linear |
Choose the correct answer from the options given below: [2024]
(A)–(IV), (B)–(I), (C)–(II), (D)–(III)
(A)–(I), (B)–(IV), (C)–(III), (D)–(II)
(A)–(I), (B)–(III), (C)–(II), (D)–(IV)
(A)–(IV), (B)–(III), (C)–(II), (D)–(I)
(1)
Match List I with List II
| List I (Molecular/Species) | List II (Property/Shape) | ||
| A. | I. | Paramagnetic | |
| B. | II. | Diamagnetic | |
| C. | III. | Tetrahedral | |
| D. | IV. | Linear |
Choose the correct answer from the options given below: [2024]
A–III, B–IV, C–II, D–I
A–IV, B–I, C–III, D–II
A–II, B–III, C–I, D–IV
A–III, B–I, C–II, D–IV
(4)
Match List I with List II.
| List I (Hybridization) | List II (Orientation in Space) | ||
| A. | I. | Trigonal bipyramidal | |
| B. | II. | Octahedral | |
| C. | III. | Tetrahedral | |
| D. | IV. | Square planar |
Choose the correct answer from the options given below: [2024]
A–IV, B–III, C–I, D–II
A–II, B–I, C–IV, D–III
A–III, B–IV, C–I, D–II
A–III, B–I, C–IV, D–II
(3)
Match List I with List II
| List I (Compound/Species) | List II (Shape/Geometry) | ||
| A. | I. | Tetrahedral | |
| B. | II. | Pyramidal | |
| C. | III. | See Saw | |
| D. | IV. | Bent T-Shape |
Choose the correct answer from the options given below: [2024]
A–III, B–II, C–IV, D–I
A–II, B–IV, C–III, D–I
A–II, B–III, C–I, D–IV
A–III, B–IV, C–II, D–I
(4)
Match List I with List II
| List I (Molecule) | List II (Shape) | ||
| A. | I. | Square pyramidal | |
| B. | II. | Tetrahedral | |
| C. | III. | Trigonal pyramidal | |
| D. | IV. | Trigonal bipyramidal |
Choose the correct answer from the options given below: [2024]
A–IV, B–III, C–I, D–II
A–II, B–IV, C–I, D–III
A–III, B–IV, C–I, D–II
A–III, B–I, C–IV, D–II
(4)
In which one of the following pairs the central atoms exhibit hybridization? [2024]
and
and
and
and
(3)
