Wave and Acoustics | Physics JEE previous year questions with Solutions

(A) $v = \sqrt{\frac{γ R T}{M}} = \sqrt{\frac{1.4 \times 8.3 \times 273}{32 \times 10^{- 3}}}$

$= 314.8541 ≃ 315 m / s$

(3)

We know for point source, $I \propto \frac{1}{r^{2}} = \frac{K}{4 π r^{2}}$

$r_{1} = 2 m, r_{2} = 4 m = 2 r_{1}$

$I_{0} = 16 \times 10^{- 8} {W/m}^{2}$

at 2m, $I_{1} = \frac{I_{0}}{{(2)}^{2}} = \frac{16 \times 10^{- 8}}{4}$

$I_{1} = 4 \times 10^{- 8}$

At 4m, $I_{2} = \frac{I_{0}}{4^{2}} = \frac{16 \times 10^{- 8}}{16} = 10^{- 8}$

$| I_{2} - I_{1} |$ $= 3 \times 10^{- 8} {W/m}^{2}, x = 3$

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