Q 1 :    

Two gases A and B are filled at the same pressure in separate cylinders with movable pistons of radius rA and rB, respectively. On supplying an equal amount of heat to both the systems reversibly under constant pressure, the pistons of gas A and B are displaced by 16 cm and 9 cm, respectively. If the change in their internal energy is the same, then the ratio rArB is equal to                [2025]
 

  • 23

     

  • 32

     

  • 43

     

  • 34

     

(4)

Given, pressure, P=constantPA=PB

Also, ΔUA=ΔUB

From first law of thermodynamics

         ΔQA=ΔUA+ΔWA

ΔQA=ΔUA+PA(16)×AA                     ...(i)

      ΔQB=ΔUB+ΔWB

ΔQB=ΔUB+PB(9)×AB                        ...(ii)

Given ΔQA=ΔQB

ΔUA+PA(16)AA=ΔUB+PB(9)×AB

16×π×rA2=9×π×rB2

(rArB)2=916rArB=34



Q 2 :    

A thermodynamic system is taken through the cycle abcda. The work done by the gas along the path bc is            [2024]

[IMAGE 102]
 

  • zero

     

  • 30 J

     

  • - 90 J

     

  • - 60 J

     

(1)

As volume is constant along the path bc, it is an isochoric process.

[IMAGE 103]

From 1st law of thermodynamics, work done for isochoric process is, W=PΔV

As, ΔV=constant, so W=0J 
 



Q 3 :    

A sample of 0.1 g of water at 100°C and normal pressure (1.013×105N m-2) requires 54 cal of heat energy to convert to steam at 100°C. If the volume of the steam produced is 167.1 cc, the change in internal energy of the sample is              [2018]
 

  • 104.3 J

     

  • 208.7 J

     

  • 42.2 J

     

  • 84.5 J

     

(2)

Using first law of thermodynamics, ΔQ=ΔU+ΔW

  54×4.18=ΔU+1.013×105(167.1×10-6-0)

  ΔU=208.7J