The p-Block Elements NEET PYQ | Important Questions for NEET Preparation

Q 1 :

Which of the following is incorrect statement? [2019]

${SnF}_{4}$ is ionic in nature.
${PbF}_{4}$ is covalent in nature.
${SiCl}_{4}$ is easily hydrolysed.
${GeX}_{4}$ ( $X = F, Cl, Br, I$ ) is more stable than ${GeX}_{2}$ .

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(2)

Generally, the halides of group-14 elements are covalent in nature. ${PbF}_{4}$ and ${SnF}_{4}$ are exceptions which are ionic in nature.

Q 2 :

Which of the following species is not stable? [2019]

${[{SiCl}_{6}]}^{2 -}$
${[{SiF}_{6}]}^{2 -}$
${[{GeCl}_{6}]}^{2 -}$
${[Sn {(OH)}_{6}]}^{2 -}$

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(1)

${[{SiCl}_{6}]}^{2 -}$ is not stable due to steric hindrance by large sized $Cl$ atoms.

Q 3 :

It is because of inability of ${ns}^{2}$ electrons of the valence shell to participate in bonding that [2017]

${Sn}^{2 +}$ is oxidising while ${Pb}^{4 +}$ is reducing
${Sn}^{2 +}$ and ${Pb}^{2 +}$ are both oxidising and reducing
${Sn}^{4 +}$ is reducing while ${Pb}^{4 +}$ is oxidising
${Sn}^{2 +}$ is reducing while ${Pb}^{4 +}$ is oxidising

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(4)

The inertness of $s$ -subshell electrons towards bond formation is known as inert pair effect. This effect increases down the group thus, for Sn, +4 oxidation state is more stable, whereas, for Pb, +2 oxidation state is more stable, i.e., ${Sn}^{2 +}$ is reducing while ${Pb}^{4 +}$ is oxidising.

Q 4 :

Choose the correct statement: [2022]

Both diamond and graphite gray are used as dry lubricants.
Diamond and graphite have two polgct dimension afof 14network.
Diamond is covalent and graphite is ionic.
Diamond is $s p ³$ hybridised and graphite is $s p ²$ hybridized.

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(4)

Topic Question Set

Q 1 :

Which of the following is incorrect statement? [2019]

Q 2 :

Which of the following species is not stable? [2019]

Q 3 :

It is because of inability of ${ns}^{2}$ electrons of the valence shell to participate in bonding that [2017]

Q 4 :

Choose the correct statement: [2022]

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