Equilibrium NEET PYQ PDF Download with Answers

0

072920 77839
info@smartachievers.in

Topic Question Set

Q 1 :
The equilibrium concentrations of the species in the reaction $A + B ⇌ C + D$ are 2, 3, 10 and 6 mol $L^{- 1}$ , respectively at 300 K. $Δ G °$ for the reaction is (R = 2 cal/mol K) [2023]

-1381.80 cal
-13.73 cal
1372.60 cal
-137.26 cal

1

2

3

4

(1)

$A + B ⇌ C + D$

$K = \frac{[C] [D]}{[A] [B]} = \frac{10 \times 6}{2 \times 3} = 10$

$Δ G ° = - R T \ln K$

$Δ G ° = - 2.303 R T \log K$

$Δ G ° = - 2.303 \times 2 \times 300 \times \log 10$

$= - 2.303 \times 2 \times 300 = - 1381.80$ $cal$

Q 2 :
Hydrolysis of sucrose is given by the following reaction: $Sucrose + H_{2} O ⇌ Glucose + Fructose$ . If the equilibrium constant $(K_{C})$ is $2 \times 10^{13}$ at 300 K, the value of $Δ_{r} G °$ at the same temperature will be [2020]

$- 8.314 {J mol}^{- 1} K^{- 1} \times 300 K \times \ln (2 \times 10^{13})$
$8.314 {J mol}^{- 1} K^{- 1} \times 300 K \times \ln (2 \times 10^{13})$
$8.314 {J mol}^{- 1} K^{- 1} \times 300 K \times \ln (3 \times 10^{13})$
$- 8.314 {J mol}^{- 1} K^{- 1} \times 300 K \times \ln (4 \times 10^{13})$

1

2

3

4

(1)

$Δ G = Δ G ° + R T \ln Q$

At equilibrium, $Δ G = 0$ and $Q = K_{C}$

$∴$ $0 = Δ G ° + R T \ln K_{C}$

$\Rightarrow Δ G ° = - R T \ln K_{C}$

$= - 8.314 {J K}^{- 1} {mol}^{- 1} \times 300 K \times \ln (2 \times 10^{13})$

Q 3 :
Which of the following statements is correct for a reversible process in a state of equilibrium? [2015]

$Δ G ° = - 2.30 R T \log K$
$Δ G ° = 2.30 R T \log K$
$Δ G = - 2.30 R T \log K$
$Δ G = 2.30 R T \log K$

1

2

3

4

(1)

Want Us to Email you About Special Offers & Updates?