Given below are two statements:
Statement I : Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273–278 K. It decomposes easily in the dry state.
Statement II : Insertion of iodine into the benzene ring is difficult and hence iodobenzene is prepared through the reaction of benzenediazonium salt with KI.
In the light of the above statements, choose the most appropriate answer from the options given below: [2025]
Statement I is correct but Statement II is incorrect.
Statement I is incorrect but Statement II is correct.
Both Statement I and Statement II are correct.
Both Statement I and Statement II are incorrect.
(3)
Benzenediazonium chloride is prepared by the reaction of aniline with nitrous acid at 273–278 K. It decomposes easily in the dry state. So, statement I is correct. Iodine is not easily introduced into the benzene ring directly thus, iodobenzene is prepared by treatment of benzene diazonium salt with KI. Hence, statement II is also correct.
The major product X formed in the following reaction sequence is [2024]
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(3)
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Choose the correct sequence of reagents in the conversion of 4-nitrotoluene to 2-bromotoluene. [2023]
(3)
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Identify the product in the following reaction: [2023]
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(4)
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The product formed from the following reaction sequence is [2022]
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(4)
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The reagent in ‘R’ in the given sequence of chemical reaction is [2021]
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CuCN/KCN
(3)
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A given nitrogen-containing aromatic compound ‘A’ reacts with Sn/HCl, followed by to give an unstable compound ‘B’. ‘B’, on treatment with phenol, forms a beautiful coloured compound ‘C’ with the molecular formula . The structure of compound ‘A’ is [2016]
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(2)
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