Q 1 :

The correct order of decreasing basic strength of the given amines is          [2025]

• N-ethylethanamine > ethanamine > N-methylaniline > benzenamine

   

• benzenamine > ethanamine > N-methylaniline > N-ethylethanamine

   

• N-methylaniline > benzenamine > ethanamine > N-ethylethanamine

   

• N-ethylethanamine > ethanamine > benzenamine > N-methylaniline

   

Q 2 :

Which one of the following compounds does not decolourize bromine water?             [2025]

Q 3 :

The major product D formed in the following reaction sequence is               [2024]

• 

   

• 

   

• ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}$

   

• ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$

   

Q 4 :

The compound that does not undergo Friedel–Crafts alkylation reaction but gives a positive carbylamine test is             [2024]

• aniline

   

• pyridine

   

• N-methylaniline

   

• triethylamine

   

Q 5 :

Given below are two statements:

Statement I : Aniline does not undergo Friedel–Crafts’ alkylation reaction.

Statement II : Aniline cannot be prepared through Gabriel synthesis.

In the light of the above statements, choose the correct answer from the options given below :          [2024]

• Both Statement I and Statement II are true.

   

• Both Statement I and Statement II are false.

   

• Statement I is correct but Statement II is false.

   

• Statement I is incorrect but Statement II is true.

   

Q 6 :

Which amongst the following compounds/species is least basic?            [2023]

Q 7 :

Given below are two statements:

Statement–I : Primary aliphatic amines react with ${\mathrm{HNO}}_2$ to give unstable diazonium salts.

Statement–II : Primary aromatic amines react with ${\mathrm{HNO}}_2$ to form diazonium salts which are stable even above 300 K.

In the light of the above statements, choose the most appropriate answer from the options given below:                   [2022]

• Both statement–I and statement–II are correct.

   

• Both statement–I and statement–II are incorrect.

   

• Statement–I is correct but statement–II is incorrect.

   

• Statement–I is incorrect but statement–II is correct.

   

Q 8 :

Identify the compound that will react with Hinsberg’s reagent to give a solid which dissolves in alkali.          [2021]

Q 9 :

Which of the following amines will give the carbylamine test?           [2020]

Q 10 :

The correct order of the basic strength of methyl substituted amines in aqueous solution is          [2019]
 

• ${\mathrm{CH}}_3{\mathrm{NH}}_2>{\left({\mathrm{CH}}_3\right)}_2\mathrm{NH}>{\left({\mathrm{CH}}_3\right)}_3\mathrm{N}$

   

• ${\left({\mathrm{CH}}_3\right)}_2\mathrm{NH}>{\mathrm{CH}}_3{\mathrm{NH}}_2>{\left({\mathrm{CH}}_3\right)}_3\mathrm{N}$

   

• ${\left({\mathrm{CH}}_3\right)}_3\mathrm{N}>{\mathrm{CH}}_3{\mathrm{NH}}_2>{\left({\mathrm{CH}}_3\right)}_2\mathrm{NH}$

   

• ${\left({\mathrm{CH}}_3\right)}_3\mathrm{N}>{\left({\mathrm{CH}}_3\right)}_2\mathrm{NH}>{\mathrm{CH}}_3{\mathrm{NH}}_2$

   

Q 11 :

The amine that reacts with Hinsberg’s reagent to give an alkali insoluble product is            [2019]

Q 12 :

Nitration of aniline in strong acidic medium also gives m-nitroaniline because            [2018]

• inspite of substituents nitro group always goes to only m-position

   

• in electrophilic substitution reactions amino group is meta directive

   

• in absence of substituents nitro group always goes to m-position

   

• in acidic (strong) medium aniline is present as anilinium ion.

   

Q 13 :

The correct increasing order of basic strength for the following compounds is             [2017]

• III < I < II

   

• III < II < I

   

• II < I < III

   

• II < III < I

   

Q 14 :

The correct statement regarding the basicity of arylamines is                  [2016]

• arylamines are generally more basic than alkylamines because of aryl group

   

• arylamines are generally more basic than alkylamines, because the nitrogen atom in arylamines is sp-hybridised

   

• arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalised by interaction with the aromatic ring $\mathrm{\pi }$-electron system

   

• arylamines are generally more basic than alkylamines because the nitrogen lone-pair electrons are not delocalised by interaction with the aromatic ring $\mathrm{\pi }$-electron system.