Q 1 :

The correct statements from the following are:                                                     [2024]

A. The strength of anionic ligands can be explained by crystal field theory.

B. Valence bond theory does not give a quantitative interpretation of kinetic stability of coordination compounds.

C. The hybridization involved in the formation of [Ni(CN)4]2-complex is dsp2.

D. The number of possible isomer(s) of cis-[PtCl2(en)2]2+is one.

Choose the correct answer from the options given below:

  • B, C only

     

  • A, C only

     

  • A, D only

     

  • B, D only

     

(1)

(A) Crystal field theory helps us in arranging the ligands in increasing order of their crystal field splitting strength.

(B) Valence bond theory does not give a quantitative interpretation of the thermodynamic or kinetic stabilities of coordination compounds.

(C) [Ni(CN)4]2- 

       Oxidation number of Ni = +2

       Ni2+:[Ar]3d818 

  

     CN- is a strong field ligand, hence it causes pairing of 3d8 electrons, then causes dsp2 hybridization using 3d, 4s, and 4p orbitals.

(D) cis- [PtCl2(en)2]2+has a pair of enantiomers.



Q 2 :

'X' is the number of acidic oxides among VO2,V2O3,CrO3,V2O5 and Mn2O7. The primary valency of cobalt in [Co(H2NCH2CH2NH2)3]2(SO4)3 is Y.  

The value of X + Y is:                           [2025]

  • 5

     

  • 4

     

  • 2

     

  • 3

     

(1)

Oxide Nature
V2O3 Basic
VO2 Basic
V2O5 Amphoteric
CrO3 Acidic
Mn2O7 Acidic, thus X = 2

 

Primary valency is oxidation state. Oxidation state of Co in [Co(H2NCH2CH2NH2)3]2(SO4)3 is +3. So Y = 3. X + Y = 5.



Q 3 :

'X' is the number of electrons in t2g orbitals of the most stable complex ion among [Fe(NH3)6]3+, [Fe(Cl)6]3-,[Fe(C2O4)3]3- and [Fe(H2O)6]3+.  The nature of oxide of vanadium of the type V2Ox is:            [2025]

  • Acidic

     

  • Neutral

     

  • Basic

     

  • Amphoteric

     

(4)

Because of chelation effect, [Fe(C2O4)3]3- is most stable. As C2O42- is a weak field ligand, Fe3+ (3d5) in [Fe(C2O4)3]3- splits as t2g3eg2.  Thus, [Fe(C2O4)3]3- has five unpaired electrons. V2O5 is amphoteric.

 



Q 4 :

Total number of molecules/species from the following which will be paramagnetic is _________.  

O2,O2+,O2-,NO,NO2,CO,K2[NiCl4],[Co(NH3)6]Cl3,K2[Ni(CN)4]                   [2025]
 



(6)

Species Electronic configuration/structure Magnetic nature
O2 σ1s2, σ*1s2, σ2s2, σ*2s2, σ2pz2, π2px2, π2py2, π*2px1, π*2py1 Paramagnetic
O2+ σ1s2, σ*1s2, σ2s2, σ*2s2, σ2pz2, π2px2, π2py2, π*2px1 Paramagnetic
O2- σ1s2, σ*1s2, σ2s2, σ*2s2, σ2pz2, π2px2, π2py2,π*2px2, π*2py1 Paramagnetic
NO σ1s2, σ*1s2, σ2s2, σ*2s2, σ2pz2, π2px2, π2py2, π*2px1 Paramagnetic
NO2 Paramagnetic
CO σ1s2, σ*1s2, σ2s2, π2px2, π2py2, σ2pz, σ*2s2 Diamagnetic
K2[NiCl4] Paramagnetic
[Co(NH3)6]Cl3 Diamagnetic
K2[Ni(CN)4] Diamagnetic

 



Q 5 :

A transition metal (M) among Mn, Cr, Co and Fe has the highest standard electrode potential (M3+/M2+).  It forms a metal complex of the type [M(CN)6]4-.  The number of electrons present in the eg orbital of the complex is ________.         [2025]  



(1)

Among Cr, Mn, Fe and Co, highest M3+/M2+ potential is of Co.  

  Cr Mn Fe Co
M3+/M2+ (in V) –0.41 +1.57 +0.77 +1.97

 

Thus the complex is [Co(CN)6]4-.

Oxidation number of Co = +2, Co2+=[Ar]183d7. As CN- is a strong field ligand, 3d7 in octahedral field splits as t2g6eg1. Number of electrons in eg is 1.

 



Q 6 :

[Ni(PPh3)2Cl2]  is a paramagnetic complex. Identify the INCORRECT statements about this complex.

A. The complex exhibits geometrical isomerism.
B. The complex is white in colour.
C. The calculated spin-only magnetic moment of the complex is 2.84 BM.
D. The calculated CFSE (Crystal Field Stabilization Energy) of Ni in this complex is 0.8Δ0.
E. The geometrical arrangement of ligands in this complex is similar to that in Ni(CO)4.

Choose the correct answer from the options given below :        [2026]

  • C, D and E Only

     

  • A, B and D Only

     

  • C and D Only

     

  • A and B Only

     

(2)

[Ni(PPh3)2Cl2]

Given : Paramagnetic complex hence it must be tetrahedral so

Crystal field splitting :

[IMAGE 183]

(A) Tetrahedral complex does not show geometrical isomerism.

(B) Complex is blue in colour

(C) Calculated spin only magnetic moment of the complex is 2.84 B.M.

(D) C.F.S.E.=-0.6Δt(4)+0.4Δt(4)

         =-0.8Δt (not -0.8Δo)

(E) Ni(CO)4 is also tetrahedral

Hence only A, B, D correct.