Q 1 :    

The correct statements from the following are:                                                     [2024]

A. The strength of anionic ligands can be explained by crystal field theory.

B. Valence bond theory does not give a quantitative interpretation of kinetic stability of coordination compounds.

C. The hybridization involved in the formation of [Ni(CN)4]2-complex is dsp2.

D. The number of possible isomer(s) of cis-[PtCl2(en)2]2+is one.

Choose the correct answer from the options given below:

  • B, C only

     

  • A, C only

     

  • A, D only

     

  • B, D only

     

(1)

(A) Crystal field theory helps us in arranging the ligands in increasing order of their crystal field splitting strength.

(B) Valence bond theory does not give a quantitative interpretation of the thermodynamic or kinetic stabilities of coordination compounds.

(C) [Ni(CN)4]2- 

       Oxidation number of Ni = +2

       Ni2+:[Ar]3d818 

  

     CN- is a strong field ligand, hence it causes pairing of 3d8 electrons, then causes dsp2 hybridization using 3d, 4s, and 4p orbitals.

(D) cis- [PtCl2(en)2]2+has a pair of enantiomers.



Q 2 :    

'X' is the number of acidic oxides among VO2,V2O3,CrO3,V2O5 and Mn2O7. The primary valency of cobalt in [Co(H2NCH2CH2NH2)3]2(SO4)3 is Y.  

The value of X + Y is:                           [2025]

  • 5

     

  • 4

     

  • 2

     

  • 3

     

(1)

Oxide Nature
V2O3 Basic
VO2 Basic
V2O5 Amphoteric
CrO3 Acidic
Mn2O7 Acidic, thus X = 2

 

Primary valency is oxidation state. Oxidation state of Co in [Co(H2NCH2CH2NH2)3]2(SO4)3 is +3. So Y = 3. X + Y = 5.



Q 3 :    

'X' is the number of electrons in t2g orbitals of the most stable complex ion among [Fe(NH3)6]3+, [Fe(Cl)6]3-,[Fe(C2O4)3]3- and [Fe(H2O)6]3+.  The nature of oxide of vanadium of the type V2Ox is:            [2025]

  • Acidic

     

  • Neutral

     

  • Basic

     

  • Amphoteric

     

(4)

Because of chelation effect, [Fe(C2O4)3]3- is most stable. As C2O42- is a weak field ligand, Fe3+ (3d5) in [Fe(C2O4)3]3- splits as t2g3eg2.  Thus, [Fe(C2O4)3]3- has five unpaired electrons. V2O5 is amphoteric.

 



Q 4 :    

Total number of molecules/species from the following which will be paramagnetic is _________.  

O2,O2+,O2-,NO,NO2,CO,K2[NiCl4],[Co(NH3)6]Cl3,K2[Ni(CN)4]                   [2025]
 



(6)

Species Electronic configuration/structure Magnetic nature
O2 σ1s2, σ*1s2, σ2s2, σ*2s2, σ2pz2, π2px2, π2py2, π*2px1, π*2py1 Paramagnetic
O2+ σ1s2, σ*1s2, σ2s2, σ*2s2, σ2pz2, π2px2, π2py2, π*2px1 Paramagnetic
O2- σ1s2, σ*1s2, σ2s2, σ*2s2, σ2pz2, π2px2, π2py2,π*2px2, π*2py1 Paramagnetic
NO σ1s2, σ*1s2, σ2s2, σ*2s2, σ2pz2, π2px2, π2py2, π*2px1 Paramagnetic
NO2 Paramagnetic
CO σ1s2, σ*1s2, σ2s2, π2px2, π2py2, σ2pz, σ*2s2 Diamagnetic
K2[NiCl4] Paramagnetic
[Co(NH3)6]Cl3 Diamagnetic
K2[Ni(CN)4] Diamagnetic

 



Q 5 :    

A transition metal (M) among Mn, Cr, Co and Fe has the highest standard electrode potential (M3+/M2+).  It forms a metal complex of the type [M(CN)6]4-.  The number of electrons present in the eg orbital of the complex is ________.         [2025]  



(1)

Among Cr, Mn, Fe and Co, highest M3+/M2+ potential is of Co.  

  Cr Mn Fe Co
M3+/M2+ (in V) –0.41 +1.57 +0.77 +1.97

 

Thus the complex is [Co(CN)6]4-.

Oxidation number of Co = +2, Co2+=[Ar]183d7. As CN- is a strong field ligand, 3d7 in octahedral field splits as t2g6eg1. Number of electrons in eg is 1.